Question
In a rather alphabetically convenient scheme, the Jemmis rules require a cluster to have m + n + o + p − q pairs of these things. For 10 points each:
[10e] Name these things, “skeletal” pairs of which are counted by Wade’s rules. In a Lewis diagram, these things are indicated by dots placed around atomic symbols.
ANSWER: electron pairs [or lone pairs; or nonbonding electrons; accept skeletal electron pairs]
[10m] Polyhedral skeletal electron pair theory is used to predict the structure of clusters of this element, as in Wade’s rules. The canonical 3-center-2-electron bond is found in a compound containing this element and hydrogen.
ANSWER: boron [accept diborane or borane]
[10h] Wade’s rules give this prefix to a boron cluster that has n vertices and n + 1 skeletal electron pairs. This prefix, contrasted with nido- and arachno-, indicates that a cluster compound is a complete deltahedron.
ANSWER: closo-borane [or closo clusters]
<Chemistry>
Summary
| 2024 ACF Winter at Clemson | 2024-11-16 | Y | 1 | 20.00 | 100% | 100% | 0% |
| 2024 ACF Winter at Lehigh | 2024-11-16 | Y | 6 | 13.33 | 83% | 33% | 17% |
| 2024 ACF Winter at Northwestern | 2024-11-16 | Y | 9 | 18.89 | 100% | 78% | 11% |
| 2024 ACF Winter at Ohio State | 2024-11-16 | Y | 7 | 15.71 | 100% | 57% | 0% |
| 2024 ACF Winter at Online | 2024-11-16 | Y | 8 | 11.25 | 100% | 13% | 0% |
| 2024 ACF Winter at UBC | 2024-11-16 | Y | 3 | 16.67 | 100% | 33% | 33% |
| 2024 ACF Winter at Central Florida | 2024-11-16 | Y | 5 | 14.00 | 100% | 20% | 20% |
Data
| CWRU B (UG) | Pitt B (UG) | 10 | 10 | 0 | 20 |
| Kenyon A (UG) | Kenyon B (DII) | 10 | 0 | 0 | 10 |
| Michigan A | Pitt A | 10 | 10 | 0 | 20 |
| Michigan State A | Michigan B | 10 | 10 | 0 | 20 |
| Ohio State C (DII) | Michigan C (UG) | 10 | 0 | 0 | 10 |
| Michigan State C (UG) | CWRU D (DII) | 10 | 0 | 0 | 10 |
| Ohio State A (UG) | Ohio State B (DII) | 10 | 10 | 0 | 20 |