Question

This compound and an alkane are side products of a reaction in which a thiohydroxamate ester is attacked by a radical initiator. Sodium phenoxide undergoes an electrophilic substitution with this compound as an intermediate of the Kolbe-Schmitt reaction. Ketoacids in the beta position more readily produce a molecule of this compound when heated. Prior to (10[1])halogenation, this compound's production creates two radicals in the Hunsdiecker (HUNTS-dee-kur) reaction. Reacting this compound with methylmagnesium bromide followed by acidic workup (10[1])yields acetic acid. Heating limestone to produce quicklime releases this (10[1])compound as (-5[1])waste. Organic solvents (10[1])are slowly poured over this compound's solid form to create slurries for cooling (-5[1])baths. This is the main reactant used in carboxylation reactions. For 10 points, name this compound found (-5[1])in dry (10[2])ice. (10[2])■END■

ANSWER: carbon dioxide [or CO2] (The first clue is the Barton decarboxylation.)
<Sean Farrell , Science - Chemistry - Organic>
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Summary

2023 NASAT06/17/2023Y8100%0%38%100.13

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PlayerTeamOpponentBuzz PositionValue
Caleb ZhaoMaryland RedIllinois Blue5410
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Shreyas SinghIllinois OrangeNew Jersey B8610
Aidan LimAsia AKentucky A88-5
Adam SmithCaliforniaVirginia9110
Rohan NavaneethaOhioMissouri A104-5
Saketh DontarajuIllinois WhiteNew Jersey A121-5
Aldric BenalanNew Jersey AIllinois White12310
Braxton DavisMissouri AOhio12310
Will ParocaiKentucky AAsia A12410
Owen ArnesonMissouri BArkansas12410