Question
The Kutta condition states that bodies with sharp trailing edges will change this quantity to hold the stagnation point at the trailing edge. For 10 points each:
[10h] Name this quantity that is multiplied by fluid density and fluid velocity far upstream to give the lift per unit span according to the Kutta-Joukowski theorem.
ANSWER: circulation
[10m] The Kutta-Joukowski theorem applies when these entities are thin and have an infinite span. Wings are examples of these lift generating entities.
ANSWER: airfoils [or aerofoils]
[10e] Airfoils experience skin friction which contributes to a coefficient named for this force that opposes motion and counteracts thrust.
ANSWER: drag force [accept air resistance; accept fluid resistance; do NOT accept or prompt on “resistance” alone]
<SP, Physics>
Summary
| 2023 ILLIAC (Cornell) | 2023-10-21 | Y | 4 | 15.00 | 100% | 50% | 0% |
| 2023 ILLIAC (Mainsite) | 2023-10-21 | Y | 8 | 16.25 | 100% | 63% | 0% |
Data
| WUSTL | Chicago A | 0 | 10 | 10 | 20 |
| Missouri | Purdue B | 0 | 10 | 10 | 20 |
| Ohio State A | Purdue A | 0 | 0 | 10 | 10 |
| Chicago D | Ohio State B | 0 | 0 | 10 | 10 |
| Chicago C | Ohio State C | 0 | 10 | 10 | 20 |
| Chicago B | Purdue C | 0 | 10 | 10 | 20 |
| Michigan A | SIUE A | 0 | 10 | 10 | 20 |
| Michigan B | SIUE B | 0 | 0 | 10 | 10 |