Round 9: The Mystery of the Sinatra Road vs. number of tang poems = 3 times the number of schools of thought = 100 times the number of kingdoms
The Mystery of the Sinatra Road
335
| Jason Golfinos | 0 | 2 | 4 | 0 |
| Eric Chen | 0 | 3 | 0 | 30 |
| Stephen Liu | 2 | 5 | 1 | 75 |
| 12 bonuses for 230 points (19.17 PPB) | ||||
number of tang poems = 3 times the number of schools of thought = 100 times the number of kingdoms
150
| Jason Cheng | 0 | 2 | 0 | 20 |
| P.C. Chauhan | 0 | 3 | 0 | 30 |
| Steven Yuan | 0 | 3 | 0 | 30 |
| 8 bonuses for 70 points (8.75 PPB) | ||||